0.1x^2=0.000018x

Solution for 0.1x^2=0.000018x equation:

0.1x^2=0.000018x

We move all terms to the left:

0.1x^2-(0.000018x)=0

We add all the numbers together, and all the variables

0.1x^2-(+0.000018x)=0

We get rid of parentheses

0.1x^2-0.000018x=0

We add all the numbers together, and all the variables

0.1x^2-5x-1.8E=0

We add all the numbers together, and all the variables

0.1x^2-5x-4.8929072912263=0

a = 0.1; b = -5; c = -4.8929072912263;
Δ = b2-4ac
Δ = -52-4·0.1·(-4.8929072912263)
Δ = 26.957162916491
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{26.957162916491}}{2*0.1}=\frac{5-\sqrt{26.957162916491}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{26.957162916491}}{2*0.1}=\frac{5+\sqrt{26.957162916491}}{0.2}
$